北邮2011-2012学年《通信原理》期末考试试题(A卷)答案.pdf
1 1 N¥¡4 N¥0ÃA §(1) (2) (3) (4) (5) (6) (7) (8) (9) (10) 55 36 13 2 52 4 31 39 53 14 (11) (12) (13) (14) (15) (16) (17) (18) (19) (20) 59 48 49 12 3 18 5 59 29 12 (21) (22) (23) (24) (25) (26) (27) (28) (29) (30) 25 50 57 56 56 40 3 12 34 3 (31) (32) (33) (34) (35) (36) (37) (38) (39) (40) 3 12 3 42 38 26 8 19 41 48 B §(41) (42) (43) (44) (45) (46) (47) (48) (49) (50) 55 9 42 23 1 19 30 45 60 43 (51) (52) (53) (54) (55) (56) (57) (58) (59) (60) 15 13 51 4 36 35 33 15 29 17 (61) (62) (63) (64) (65) (66) (67) (68) (69) (70) 24 29 34 14 14 48 36 4 38 36 (71) (72) (73) (74) (75) (76) (77) (78) (79) (80) 36 4 36 25 41 8 47 5 50 13 北邮 2011-2012学年通信原理期末考试试题(A卷)答案1 2 N¥¡4 N¥¼Ã(1) Ï 3 6Ð g11g12bsincthtTg167g183g32g168g184g169g185(2) Ï 2 6Ð g11g12Ab1PfTg32(3) Ï 2 6Ð g11g12 g11g12b22j2bBA4cos1efTbfTPf PfTg83g83g32g14g32Ï2 6Ð(4)Ï3 6Ð000110 9Ã(1) Ï3 6ÐNÁ_ 1HzÈ0?NÁ_ 1/(2Tb)È ! Tb=0.5s(2) g11g12 g11 g12 g11 g12g11g12 g11g12122sin sin 11 cos10 cos122st stgt t t t tg83g83 g83g83g16g32 g32g16g32TãGÿ z ,´ wl_ '6Èjg11g12 g11g12g11g12b12110d222Tbst st TEst tg16g32g32g179Ï2 6Ðé_g62g6400 01224 2bgNN NTEEEg32g14g32Ï2 6Ðg11g12210b0b12expbTzfzNTNTg83g167g183g167g183g16g168g184g168g184g169g185g168g184g32g16g168g184g168g184g169g185Ï2 6Ð(3) TãKIB)·1y¾ ?¾2bTg16,´²)·Èj00112erfc erfc222bbbTTNNTg167g183g168g184g167g183g32g168g184g168g184g168g184g168g184g169g185g168g184g169g185Ï3 6Ð1 3 N¥¡4 N¥Ã ( 1) Ï4 6Ð42411.58sEg117g14g117g32g32È dmin=1(2)Ï 4 6Ðf1(t)f2(t)s1s2s3s4s5s6s7s8(3) Ï4 6Ð g11g122211 2p ppg16g16 g32 g16Äà (1) Ï 4 6Ðg11g121sR Bg68g14g32È128MBaud1 0.5sR g32g32g14È Rb=4Rs=32Mbps(2)Ï 4 6Ð(3)Ï4 6ÐÃ(1) Ï3 6Ð5F.15Ì_ 11101001 (2)g3g39=1/4Èg16(8 g16g39/2)=g167.875Ï3 6Ð È2q112 192Ng39g32g32 Ï3 6Ð(3) Ï 3 6Ð Rb=4h 64=256kbps1 4 N¥¡4 N¥LzÖNÎÄ 10 6ÅÖ(1)Ï 4 6Ðg11g12 g11g12 g11g12 g11g12g11g12211dddnkknkggnnngstgtt agtgttEEagttaEg102g102g102g102g102g102g32g16g102g16g102g16g16g167g183g32g168g184g169g185g32g32g166g179g179g179(2) Ï 6 6Ð (Añ>é#= _0 )g11g12 g11 g12 g11g12 g11g12s*j211dedfnTnsggastgtnTtSfGf tEEg83g102g102g102g16g102g16g16g170g186g32g16g32g172g188g179g179¦ G(f)_ g(t),´µ“? Èjg11g12s,0,TfGff WWg173g32g33g100g176g174g176g175þNÁ “r*g11g1222d2g ssE Gf f WT Tg102g16g102g32g32g32g179Ä S(f),´Ví_ WÈ !g11g12 g11g12 g11g12g11g12 g11 g12sj2 j2*j21ed ededWWfnT fnTnsfnTsaSfGftSftTSf t snTg83g83g83g16g16g16g102g102g32g32g32g32g179g179g179